Question

Integration question.

The question is to find the integral of
-cosec6xcis6x
Plz help!

I thought to first integrate
-cosec6x
Which is 1/sin (6x).....a little stuck

Answer 1

can you rewrite that properly

Answer 2

Integrate
-cosec6xcot6x

Answer 3

@nincompoop can you plz help me in a ques?

Answer 4

\(\huge \int -csc (6x) cot(6x) dx \) like this?

Answer 5

Does cse mean cosec?
If so then yes

Answer 6

Ok so rewrite it as -1/sin(6x) * cos(6x)/sin(6x) then you get -cos(6x)/sin^2(6x)
Then find the derivative of sin(6x) then your finished and use the formula integ of u^ndu=u^n+1/n+1 +c

Answer 7

\(\huge -\frac{1}{sin} = -csc \)

Answer 8

\(\huge \frac{1}{tan} = cot \)

Answer 9

Does cse mean cosec?
If so then yes

Answer 10

yes

Answer 11

u-sub

Answer 12

Look thats it

Answer 13

u = 6x
du = 6 dx

Answer 14

Did you understand it?

Answer 15

v = sin(u)
dv = cos(u) du

Answer 16

those are you keys

Answer 17

Your description and point is surely very feeble my friend so you're saying the Bible is demonic?

Answer 18

In asking you a question that relates to what you've said hence fabricator

Answer 19

you really need to read the whole thing before you ruin your mind with fallacy

Answer 20

No need since i spotted an error just from the very beginning which discourages me to continue this nonsense. Have a great day