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Mathematics 21 Online
OpenStudy (anonymous):

The graph of which function has an axis of symmetry at x =-1/4 ? f(x) = 2x2 + x – 1 f(x) = 2x2 – x + 1 f(x) = x2 + 2x – 1 f(x) = x2 – 2x + 1

Nnesha (nnesha):

\[\huge\rm x=\frac{ -b }{ 2a }\] to find c-coordinate of vertex(axis of symmetry)

Nnesha (nnesha):

b and a values are \[\rm Ax^2+Bx+C\] where a=leading coefficient b=middle term c=constant term

OpenStudy (anonymous):

will give medals

OpenStudy (anonymous):

i have answer chioces listed

OpenStudy (anonymous):

@Nnesha

Nnesha (nnesha):

i know so which is your answer A , B ,C or D >

OpenStudy (anonymous):

im thinkin c

OpenStudy (anonymous):

@Nnesha

Nnesha (nnesha):

no.

OpenStudy (anonymous):

im horrible at math lol but my next guess is d

Nnesha (nnesha):

don't guess next time when you say is it B or A or D i'll ask to explain it for me

Nnesha (nnesha):

start with 1st option okay what is a and b value in that equation

OpenStudy (anonymous):

2

Nnesha (nnesha):

a=2 right b=1 x is same as 1x not substitute a and b for their value into that formula

OpenStudy (anonymous):

-1/2*2?

Nnesha (nnesha):

yes right multiply 2 times 2 ?

OpenStudy (anonymous):

-1/4

OpenStudy (anonymous):

so a is the answer

Nnesha (nnesha):

i think so :=)

OpenStudy (anonymous):

thank you!!!

Nnesha (nnesha):

you're lucky don't have to check other 3 options ...

Nnesha (nnesha):

np

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