Mathematics
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OpenStudy (anonymous):
The graph of which function has an axis of symmetry at x =-1/4 ?
f(x) = 2x2 + x – 1
f(x) = 2x2 – x + 1
f(x) = x2 + 2x – 1
f(x) = x2 – 2x + 1
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Nnesha (nnesha):
\[\huge\rm x=\frac{ -b }{ 2a }\]
to find c-coordinate of vertex(axis of symmetry)
Nnesha (nnesha):
b and a values are \[\rm Ax^2+Bx+C\]
where
a=leading coefficient
b=middle term
c=constant term
OpenStudy (anonymous):
will give medals
OpenStudy (anonymous):
i have answer chioces listed
OpenStudy (anonymous):
@Nnesha
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Nnesha (nnesha):
i know
so which is your answer A , B ,C or D >
OpenStudy (anonymous):
im thinkin c
OpenStudy (anonymous):
@Nnesha
Nnesha (nnesha):
no.
OpenStudy (anonymous):
im horrible at math lol but my next guess is d
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Nnesha (nnesha):
don't guess
next time when you say is it B or A or D
i'll ask to explain it for me
Nnesha (nnesha):
start with 1st option okay
what is a and b value in that equation
OpenStudy (anonymous):
2
Nnesha (nnesha):
a=2 right b=1
x is same as 1x
not substitute a and b for their value into that formula
OpenStudy (anonymous):
-1/2*2?
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Nnesha (nnesha):
yes right multiply 2 times 2 ?
OpenStudy (anonymous):
-1/4
OpenStudy (anonymous):
so a is the answer
Nnesha (nnesha):
i think so :=)
OpenStudy (anonymous):
thank you!!!
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Nnesha (nnesha):
you're lucky don't have to check other 3 options ...
Nnesha (nnesha):
np