Ask your own question, for FREE!
Physics 25 Online
OpenStudy (yumyum247):

Guelp please!!!

OpenStudy (yumyum247):

Can someone please check my work???

OpenStudy (yumyum247):

@Michele_Laino please yelp me!!!

OpenStudy (michele_laino):

hint: I suppose that the motion of your flowerpot is a vertical motion. Time needed to flowerpot to reach the earth surface is: \[\Large \frac{{{v_0}}}{g}\left\{ {1 + \sqrt {\frac{1}{2} + \frac{{2g{h_0}}}{{v_0^2}}} } \right\}\] where v0= 1m/sec and h0 is the maximum height reached by our flowerpot the final speed of our flowerpot, is: \[\Large \sqrt {2g{h_0} + v_0^2} \] Please use those information, and you will get your answers

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!