Question

Identify the axis of symmetry and vertex of f(x) = –2x^2 –2x–1.

Axis of symmetry: x = 0.5; Vertex: (0.5, – 0.50)
Axis of symmetry: x = – 0.5; Vertex: (– 0.5, 0.50)
Axis of symmetry: x = – 0.5; Vertex: (– 0.5, – 0.50)
Axis of symmetry: x = 0.5; Vertex: (– 0.5, – 0.50)

Answer 1

@fashionismybesty

Answer 2

http://www.mathway.com/graph/NTUxODk

this is an amazing site for graphing

Answer 3

Do you know how to write in vertex form? If involves completing the square?
\[f(x)=-2x^2-2x-1 \\ f(x)=-2(x^2+x)-1 \\ f(x)=-2(x^2+x+L)-1+2L \\ \text{ notice } -2L+2L=0 \\ \text{ we need to figure out what } L \text{ needs to be to } \\ \text{ complete the square inside that one ( )}\]

Answer 4

or http://openstudy.com/study#/updates/55de281ae4b0f9297e9bc5e7 :=)