Question

Find the quotient of quantity of 3 times x to the 3rd power plus 9 times x to the 2nd power minus 6 times x all over negative 3 times x.

x^2 − 9x + 6
−x^2 − 3x − 2
x^2 + 9x − 6
−x^2 − 3x + 2

Answer 1

\[(\frac{ 3x^3 + 9x^2 - 6x }{ -3x })\]
\[= -x^2 - 3x + 2\]

Answer 2

Just divide the term from each term above.

Answer 3

Oh, wow, thanks so much :D