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Given ƒ(x) = 3x - 1 and g(x)= -x + 6, find ƒ(-2) + g(5). -6 6 8
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just replace the x in f(x) ( that is 3x - 1) by -2 and work it out then replace the x in -x + 6 by 5 and work it out and add the 2 results
wait what im confused
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