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Mathematics 20 Online
OpenStudy (anonymous):

Can some one please help me step by step to solve these two problems? Screen shots included. Medal!

OpenStudy (anonymous):

OpenStudy (anonymous):

I'm not sure... I may get the question wrong. You should probably use this formula A=1/2 BH

OpenStudy (anonymous):

This is my first time doing this I need like a step by step on how to do it

OpenStudy (anonymous):

Hmm, I'm sorry.. I dont get it either lol really wish I did.. but it's confusing

OpenStudy (calculusxy):

Use the Pythagorean Theorem \[a^2 + b^2 = c^2 \]

OpenStudy (welshfella):

use pythagorss theorem

OpenStudy (calculusxy):

For question 1 we know that a = 16 and b = 63 so let's plug that into the formula to find c (hypotenuse) \[16^2 + 63^2 = c^2 \]

OpenStudy (anonymous):

16^2 + 63^ =c^2 lol

OpenStudy (calculusxy):

Do you understand how to find the answer to this problem?

OpenStudy (anonymous):

4,225?

OpenStudy (calculusxy):

Good and then find the aquaria root of 4,225 because when c is being squared, it equals to 4225.

OpenStudy (calculusxy):

*square root

OpenStudy (anonymous):

65

OpenStudy (calculusxy):

correct!

OpenStudy (anonymous):

Thank you can you wait until I do the second problem so i can see if its right?

OpenStudy (calculusxy):

Sure !

OpenStudy (anonymous):

would the answer be 3.5805.?

OpenStudy (calculusxy):

Let's check! \[a^2 + 2.1^2 = 2.9^2\] \[a^2 = 4\] (because 2.9^2 - 2.1^2) \[a = \sqrt4\]

OpenStudy (anonymous):

ohhh okay! I just plugged it in wrong

OpenStudy (anonymous):

Thank you! I'll contact you if i need help with anything else

OpenStudy (calculusxy):

Sure! and You're welcome :)

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