Question

Part A: Factor 3x2y2 − 2xy2 − 8y2. Show your work. (4 points)

Part B: Factor x2 + 10x + 25. Show your work. (3 points)

Part C: Factor x2 − 36. Show your work. (3 points)

Answer 1

i need steps i have answers!
Part A.) y^2(3x+4)(x-2)
Part B.) (x-5)^2
Part C.) (x+6)(x-6)

Answer 2

@zepdrix

Answer 3

sorry I cant help u on this but I love the name :)

Answer 4

ty :}

Answer 5

yw and good luck on ur question!

Answer 6

ty

Answer 7

yw

Answer 8

\[\large\rm 3x^2y^2 − 2xy^2 − 8y^2\]What are we doing? :U Factoring this thing?

Answer 9

\[\large\rm 3x^2\color{orangered}{y^2} − 2x\color{orangered}{y^2} − 8\color{orangered}{y^2}\]Hmm there isn't a whole lot that we can do with this first one.
Notice that the last term has no x's, so we can't pull out any factor out any amount of x.
The last two terms have a 2 in them (8 is 4 times 2) but the first term does not, so we can't pull a 2 out.

You can do something with the y's though, ya?

Answer 10

Yes.

Answer 11

Oh I guess we can factor the x's after that though :3 hah

Answer 12

\[\large\rm \color{orangered}{y^2}(3x^2−2x−8)\]So you ok with that first step? :o

Answer 13

Um
(y2)(3x2+−2x+−8)
=(y2)(3x2)+(y2)(−2x)+(y2)(−8)
=3x2y2−2xy2−8y2
=3x2y2−2xy2−8y2

Answer 14

You just un-did the first step :)
Not sure why hehe

Answer 15

Opps >_<

Answer 16

I am confused on this..

Answer 17

So we're taking y^2 out of each term.