Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (irishboy123):

complex numbers

OpenStudy (irishboy123):

|z| = 2 prove \[|z^2 + 2| \ge 2\]

OpenStudy (freckles):

you said you were going to try this one @IrishBoy123 right?

OpenStudy (irishboy123):

oh yes! \(|z^2 +2 |\ge ||z|^2-|2||=|4-2| = 2\)

OpenStudy (irishboy123):

\[|z^2+2| \le |z^2|+|2|=4+2=6\]

OpenStudy (irishboy123):

\[ 2\le |z^2 + 2| \le 6\]

OpenStudy (irishboy123):

thank you @freckles

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!