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Mathematics
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complex numbers
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|z| = 2 prove \[|z^2 + 2| \ge 2\]
you said you were going to try this one @IrishBoy123 right?
oh yes! \(|z^2 +2 |\ge ||z|^2-|2||=|4-2| = 2\)
\[|z^2+2| \le |z^2|+|2|=4+2=6\]
\[ 2\le |z^2 + 2| \le 6\]
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thank you @freckles
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