Mathematics
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OpenStudy (anonymous):
Can someone please check my answers for me and help me with one problem? Screenshots included and medal!
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OpenStudy (anonymous):
OpenStudy (anonymous):
root of 75 + root of 3 = 6 root 3
OpenStudy (anonymous):
the last one is root of 21 + 7 root 2
OpenStudy (anonymous):
the first one i think is 3n^2 root 5n
OpenStudy (anonymous):
wait let me give you my answers
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OpenStudy (anonymous):
5.) √45n^2
3√5 √n^5
3n^2 √5n
6.) √75 + √3
√25 * 3 + √3
5√3 + √3
= 6√3
OpenStudy (anonymous):
both correct
OpenStudy (anonymous):
Thank you I just cant do the third one
OpenStudy (anonymous):
distribute first
OpenStudy (anonymous):
like factor?
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OpenStudy (anonymous):
Can you show me a step by step on how to solve this
OpenStudy (anonymous):
\[\sqrt{7}(\sqrt{14}+\sqrt{3}) = \sqrt{21}+7\sqrt{2}\]
OpenStudy (anonymous):
i dont know the steps i asked science
OpenStudy (anonymous):
7.) √7(√14+√3)
√7(√2*7 + √3)
√7 (√2√7+√3)
OpenStudy (anonymous):
go on
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OpenStudy (anonymous):
idk how to do it from there @Dwayne_Johnson
OpenStudy (anonymous):
@calculusxy
OpenStudy (zzr0ck3r):
\[\sqrt{7}(\sqrt{14}+\sqrt{3})=\sqrt{7}\sqrt{14}+\sqrt{7}\sqrt{3}=\sqrt{7}\sqrt{7*2}+\sqrt{7}\sqrt{3}=\sqrt{7}\sqrt{7}\sqrt{2}+\sqrt{7}\sqrt{3}\\=7\sqrt{2}+\sqrt{7}\sqrt{3}=7\sqrt{2}+\sqrt{21}\]
OpenStudy (anonymous):
thank you so much :)