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Mathematics 9 Online
OpenStudy (anonymous):

Can someone please check my answers for me and help me with one problem? Screenshots included and medal!

OpenStudy (anonymous):

OpenStudy (anonymous):

root of 75 + root of 3 = 6 root 3

OpenStudy (anonymous):

the last one is root of 21 + 7 root 2

OpenStudy (anonymous):

the first one i think is 3n^2 root 5n

OpenStudy (anonymous):

wait let me give you my answers

OpenStudy (anonymous):

5.) √45n^2 3√5 √n^5 3n^2 √5n 6.) √75 + √3 √25 * 3 + √3 5√3 + √3 = 6√3

OpenStudy (anonymous):

both correct

OpenStudy (anonymous):

Thank you I just cant do the third one

OpenStudy (anonymous):

distribute first

OpenStudy (anonymous):

like factor?

OpenStudy (anonymous):

Can you show me a step by step on how to solve this

OpenStudy (anonymous):

\[\sqrt{7}(\sqrt{14}+\sqrt{3}) = \sqrt{21}+7\sqrt{2}\]

OpenStudy (anonymous):

i dont know the steps i asked science

OpenStudy (anonymous):

7.) √7(√14+√3) √7(√2*7 + √3) √7 (√2√7+√3)

OpenStudy (anonymous):

go on

OpenStudy (anonymous):

idk how to do it from there @Dwayne_Johnson

OpenStudy (anonymous):

@calculusxy

OpenStudy (zzr0ck3r):

\[\sqrt{7}(\sqrt{14}+\sqrt{3})=\sqrt{7}\sqrt{14}+\sqrt{7}\sqrt{3}=\sqrt{7}\sqrt{7*2}+\sqrt{7}\sqrt{3}=\sqrt{7}\sqrt{7}\sqrt{2}+\sqrt{7}\sqrt{3}\\=7\sqrt{2}+\sqrt{7}\sqrt{3}=7\sqrt{2}+\sqrt{21}\]

OpenStudy (anonymous):

thank you so much :)

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