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Given that f(x) = 5x – 10 and g(x) = x + 3, solve for f(g(x)) when x = –1. –30 0 10 12
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find g(-1) first
notice g(x)=x+3 enter in -1 for x
actaully is hmm -1 well
your work isn't meaningless though it is good example
\(\bf f(x)=5x-10\qquad g(x)=x+3 \\ \quad \\ f(\quad {\color{brown}{ g(x)}} \quad )=5{\color{brown}{ g(x)}}-10\implies f(\quad {\color{brown}{ g(x)}} \quad )=5{\color{brown}{ (x+3)}}-10 \\ \quad \\ f(\quad {\color{brown}{ g({\color{blue}{ -1}})}} \quad )=5{\color{brown}{ g({\color{blue}{ -1}})}}-10\implies f(\quad {\color{brown}{ g({\color{blue}{ -1}})}} \quad )=5{\color{brown}{ ({\color{blue}{ -1}}+3)}}-10\)
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ok nevermind
:)
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