A truck is worth $80000 when purchased. It is depreciated linearly over 7 years ad has a scrap value of $6000.00. A linear equation expressing the trucks book value at the end of t years is.

I got v(t)= -74000/7(t) + 80000. Is that correct?

Question

A truck is worth $80000 when purchased. It is depreciated linearly over 7 years ad has a scrap value of $6000.00. A linear equation expressing the trucks book value at the end of t years is.

I got v(t)= -74000/7(t) + 80000. Is that correct?

anonymous · Answer

find the equation of the line through $(0,80000)$ and $(7,60000)$ if i am reading it correctly b

anonymous · Answer

b?

anonymous · Answer

is there a choice that says 
$$y=-\frac{2000}{7}x+80000$$?

anonymous · Answer

$$no, there is -52000/7t + 6000, -74000/7t+6000, 68000/7t-6000, -52000/7t+80000 and mine alongwith F none$$