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Mathematics 16 Online
OpenStudy (anonymous):

Solve for x

OpenStudy (anonymous):

\[1/(x-1) + 1/(x+2) = 1/2\]

OpenStudy (anonymous):

first add

OpenStudy (anonymous):

or else multiply both sides by \((x-1)(x+2)\)

OpenStudy (anonymous):

Including 1/2?

OpenStudy (anonymous):

yes for sure

OpenStudy (anonymous):

\[(x+2)+(x-1)=\frac{(x+2)(x-1)}{2}\]

OpenStudy (anonymous):

Wait. What I got was \[(x + 2 + x - 1)/(x-1)(x+2) = (x-1)(x+2)/2x^2+2x-4 \]

OpenStudy (triciaal):

|dw:1441086605332:dw|

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