Question

(csc(6x)+cot(6x))/(csc(6x)-cot(6x))=____
(Cot^2)(3x)
cot(3x)
(cot^2)(6x)
tan(6x)

Answer 1

i got it to (1/sin(6x)+1/tan(6x))/(1/sin(6x)-1/tan(6x)

Answer 2

hmm... let's try multiplying the top and bottom of the the original expression by the conjugate of the bottom

Answer 3

I'm thinking about using the identity
\[1+\cot^2(\theta)=\csc^2(\theta)\]
maybe

Answer 4

though this might just be easier to plug in 20 deg into the first expression
and see which one below when pluggin 20 degs gives the same result