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well to do this you need to know the mean.... as an example if the mean is 10 and the 1st value in the table is 15 \[x_{j} - \mu = 15 - 10\] does that make sense...?
Yes but that would be for the first column right??
@campbell_st
that's correct. the 2nd column just square the value in the 1st column. then sum the 2nd columm
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