A particle moves with constant acceleration of 3.2 m/s2. At t = 4 s, it is at x = 110 m; at t = 6 s, it has a velocity v = 19 m/s. Find its position at t = 6 s.

Question

irishboy123 · Answer

use the equations of motion:
$x = ut + \frac{1}{2}at^2$
$v = u + at$

plug in given information:
$110 = u (4) + \frac{1}{2}a (4)^2$
$19 = u  + a(6)$

you now have 2 unknowns and 2 equations, you can solve for u and a

then find $x(6)$