Question

the sum of three consecutive odd integers is 88 more than the largest number. Find the integer.

Answer 1

Let \(n\) be our odd integer.

The sum of it and the next two odd integers, is \(n+(n+2)+(n+4)\) where \((n+4)\) is the largest.

Then we have


\[n+(n+2)+(n+4)=88+(n+4)\]