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Mathematics 20 Online
OpenStudy (anonymous):

In the middle of town, State and Elm streets meet at an angle of 40º. A triangular pocket park between the streets stretches 100 yards along State Street and 53.2 yards along Elm Street. What formula for the area of the pocket park would you use

OpenStudy (anonymous):

A = 1/2(sin40º)(53.2 yd) A = 1/2 (sin100º)(53.2 yd) A = (100 yd)(sin50º)(53.2 yd) A = 1/2 (100 yd)(sin40º)(53.2 yd)

OpenStudy (danjs):

draw it up, looks like you are given side - angle - side values

OpenStudy (danjs):

|dw:1441237709949:dw|

OpenStudy (anonymous):

I think it's the last one.

OpenStudy (danjs):

The area of a triangle is (1/2)*base*height

OpenStudy (danjs):

maybe easier to orient it different.... |dw:1441237983462:dw|

OpenStudy (danjs):

|dw:1441238059312:dw|

OpenStudy (anonymous):

So the last one then

OpenStudy (danjs):

so the area of the red triangle is (1/2) * base * height = (1/2) * 100 * h

OpenStudy (danjs):

since h is part of a right triangle, you can use trig function to rewrite its value

OpenStudy (danjs):

you get what i did so far?, almost done

OpenStudy (anonymous):

Yeah kinda lol

OpenStudy (danjs):

Since you already know the hypotenuse, you can use sin(40) to find h, sin(40) = opposite side / hypotenuse sin(40) = h / 53.2

OpenStudy (danjs):

so h = 53.2 * sin(40)

OpenStudy (anonymous):

Omg so I was right. It's 1/2(100)(Sin40)(53.2)

OpenStudy (danjs):

yeah, you guess or do that work? :)

OpenStudy (anonymous):

Did the work just wasn't sure. Mind helping me with one more? Then I'm done

OpenStudy (danjs):

sure, start a new clean thread

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