In the middle of town, State and Elm streets meet at an angle of 40º. A triangular pocket park between the streets stretches 100 yards along State Street and 53.2 yards along Elm Street. What formula for the area of the pocket park would you use
A = 1/2(sin40º)(53.2 yd) A = 1/2 (sin100º)(53.2 yd) A = (100 yd)(sin50º)(53.2 yd) A = 1/2 (100 yd)(sin40º)(53.2 yd)
draw it up, looks like you are given side - angle - side values
|dw:1441237709949:dw|
I think it's the last one.
The area of a triangle is (1/2)*base*height
maybe easier to orient it different.... |dw:1441237983462:dw|
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So the last one then
so the area of the red triangle is (1/2) * base * height = (1/2) * 100 * h
since h is part of a right triangle, you can use trig function to rewrite its value
you get what i did so far?, almost done
Yeah kinda lol
Since you already know the hypotenuse, you can use sin(40) to find h, sin(40) = opposite side / hypotenuse sin(40) = h / 53.2
so h = 53.2 * sin(40)
Omg so I was right. It's 1/2(100)(Sin40)(53.2)
yeah, you guess or do that work? :)
Did the work just wasn't sure. Mind helping me with one more? Then I'm done
sure, start a new clean thread
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