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Algebra 17 Online
OpenStudy (countrygirl1431):

PLZ HELP!!!! Given that ƒ(x) = x² + 5x, evaluate ƒ(-2). -6 -14 7

OpenStudy (anonymous):

Okay what grade?

OpenStudy (anonymous):

just tagg me or message me when you say the grade :)

OpenStudy (campbell_st):

f(-2) is asking you to subsitute x = -2 and get a number value so its \[f(-2) = (-2)^2 + 5 \times (-2)\]

OpenStudy (countrygirl1431):

11th @west_coast

OpenStudy (countrygirl1431):

only if u ask them

OpenStudy (anonymous):

Okay f=x

OpenStudy (anonymous):

no i never asked them they just gave me it

OpenStudy (countrygirl1431):

oh well then

OpenStudy (anonymous):

so x can be anything but its to the second power or whatever

OpenStudy (anonymous):

so if x=2 its would be 2*2 you get it?

OpenStudy (anonymous):

Okay plug in all those numbers at the bottom

OpenStudy (anonymous):

So im guessing they have to equal the same as 5x?

OpenStudy (countrygirl1431):

i guess

OpenStudy (anonymous):

Okay let me do this

OpenStudy (countrygirl1431):

k

OpenStudy (anonymous):

7 doesn't work

OpenStudy (anonymous):

and -14 dosent work

OpenStudy (countrygirl1431):

so -6

OpenStudy (anonymous):

let me try -6

OpenStudy (anonymous):

uhg no

OpenStudy (anonymous):

i think im doing this wrong because 6*6 is 36 and 5*6 is 30 so

OpenStudy (anonymous):

WAIT I FORGOT TO ADD OMG WAIT

OpenStudy (anonymous):

tbh i think its -6

OpenStudy (anonymous):

i gtg but if you need more help just message me ot tagg me

OpenStudy (countrygirl1431):

k thanks

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