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Algebra
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OpenStudy (countrygirl1431):
PLZ HELP!!!!
Given that ƒ(x) = x² + 5x, evaluate ƒ(-2).
-6
-14
7
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OpenStudy (anonymous):
Okay what grade?
OpenStudy (anonymous):
just tagg me or message me when you say the grade :)
OpenStudy (campbell_st):
f(-2) is asking you to subsitute x = -2 and get a number value so its
\[f(-2) = (-2)^2 + 5 \times (-2)\]
OpenStudy (countrygirl1431):
11th @west_coast
OpenStudy (countrygirl1431):
only if u ask them
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OpenStudy (anonymous):
Okay f=x
OpenStudy (anonymous):
no i never asked them they just gave me it
OpenStudy (countrygirl1431):
oh well then
OpenStudy (anonymous):
so x can be anything but its to the second power or whatever
OpenStudy (anonymous):
so if x=2 its would be 2*2 you get it?
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OpenStudy (anonymous):
Okay plug in all those numbers at the bottom
OpenStudy (anonymous):
So im guessing they have to equal the same as 5x?
OpenStudy (countrygirl1431):
i guess
OpenStudy (anonymous):
Okay let me do this
OpenStudy (countrygirl1431):
k
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OpenStudy (anonymous):
7 doesn't work
OpenStudy (anonymous):
and -14 dosent work
OpenStudy (countrygirl1431):
so -6
OpenStudy (anonymous):
let me try -6
OpenStudy (anonymous):
uhg no
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OpenStudy (anonymous):
i think im doing this wrong because 6*6 is 36 and 5*6 is 30 so
OpenStudy (anonymous):
WAIT I FORGOT TO ADD OMG WAIT
OpenStudy (anonymous):
tbh i think its -6
OpenStudy (anonymous):
i gtg but if you need more help just message me ot tagg me
OpenStudy (countrygirl1431):
k thanks
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