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solve 8 to the power of 5 over 8 to the power of 3 show work
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think of it like \[\frac{ 8\times8\times8\times8\times8 }{ 8\times8\times8 }\]
you can cancel out 3 of the 8 at the top from 3 of the 8 at the bottom right? and now your left with two 8 at the top..... can you see this with the powwers? what can we do the powers to end up with 8^2
that's what i tried but im still confused
16
you end up with 16
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lets leave it in power form \[\frac{ 8^5 }{ 8^3 } = 8^2\]
i think u mean 64 ..
\(\bf \cfrac{\cancel{ 8}\times\cancel{ 8}\times\cancel{ 8}\times8\times8 }{ \cancel{ 8}\times \cancel{ 8}\times \cancel{ 8}}\implies ?\)
ya 64
how would i show my work
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