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A water filter has the shape of an inverted right circular cone with base radius 3 meters and height 9 meters. Water is being pumped into the filter at the rate of 10 meters3/sec. Find the rate, in meters/sec, at which the water level is rising when the water is 3 meters deep
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write down all the given things in a list, it will make it easier to start.. V = (1/3)*pi*r^2*h ...
related rates in calc 1 right?
|dw:1441329757668:dw|
dV / dt = 10 m^3 /s
put the volume formula in terms of only h or only r, by using the given ratio of the dimension values (right cone)
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then differentiate everything w.r.t. time t..
they give you dV/dt = 10 you have to solve for dh/dt and let h = 3
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