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Suppose \(f(x)\) is a rational function such that \(3 f \left( \frac{1}{x} \right) + \frac{2f(x)}{x} = x^2\) for all \(x \neq 0\). Find \(f(-2)\).
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I wonder if you get a system of equations by entering in -2 and also -1/2 you know separately.
\[3f(\frac{1}{-2})+\frac{2 f(-2)}{-2}=(-2)^2 \text{ from putting } x=-2 \\ 3f(-2)+\frac{2 f(\frac{-1}{2})}{\frac{-1}{2}}=(-\frac{1}{2})^2 \text{ from putting } x=\frac{-1}{2}\] looks like
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