Question

http://prntscr.com/8ck6iw

Answer 1

SO basically what u have to is substitute the numbers

Answer 2

I got 35 !!!!! Just substitute the numbers and solve it according to the order !

Answer 3

\[2x^2-6y+(16+4/2)+y\]work the parentheses first we get\[2(4)^2-6(3)+(16+2)+3\]\[2(4)^2-6(3)+(18)+3\]\[2(16)-18+18+3\]\[2(16)+3\]

Answer 4

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