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realtive frequency of green bar = 5 / total accidents
I did that and got A
theres no way that right though
would i be right for the first one with A
by definition, of relative frequency, we have the subsequent relative frequency for green bar: \[\Large \frac{5}{{3 + 8 + 2 + 5}} = \frac{5}{{18}} \cong 0.28\] so you are right
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similarly for red bar, we have: \[\Large \frac{8}{{3 + 8 + 2 + 5}} = \frac{4}{9} \cong 0.44\]
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