Question

Find all numbers such that the square of the number is 48 more than double the number. If you find more than one, then list all the numbers you find in increasing order, separated by commas.

Answer 1

so let x be the number

so then

\[x^2 = 2x + 48\]

or

\[x^2 - 2x - 48 = 0\]

you need to solve for x, this can be done by factoring

you will have 2 solutions, 1 positive and 1 negative

hope it helps