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if the limit of x as it approaches c of f(x) exists, then does the limit of x as it approaches c of sqrt(f(x)) exist?
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is the sqrt of a negative number defined?
no it's not
so no, it doesn't exist? because if c is any negative number then it doesn't exist?
thats what my gut tells me ....
http://www.wolframalpha.com/input/?i=limit+of+x+to++infinity%2C+sqrt%28-4x%2Fx%29 as a simple test .... the limit as x to inf of; -4x/x = -4, but its sqrt does not
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