Question

simplify

Answer 1

\[\frac{ 3a^2 }{ 4 } + \frac{ 2ab }{ 3 }+ab-a^2\]

Answer 2

I would suggest you operate those fractions:
\[\frac{ 3a^2 }{ 4 }+\frac{ 2ab }{ 3 }+ab-a^2 \]
\[\frac{ 3(3a^2)+4(2ab)+(4)(3)ab-(4)(3)a^2 }{ 12 }\]