Question

Hi, how would you integrate ∫√(3)x(2 − 4x)^(1/3). dx ??
Thanks in advance! :)

Answer 1

draw it, maybe?

that could be interpreted in any number of ways...

Answer 2

or scan or link the source

Answer 3

\[\int\limits \sqrt{3}x(2-4x)^{1/3}.dx\]

Answer 4

by parts
u = x, v' = (2-4x)^{1/3)

Answer 5

\[\int \sqrt{3}x(2-4x)^{1/3} \ dx\]
\[\sqrt{3} \int x(2-4x)^{1/3} \ dx\]

\[u = x, u' = 1\]
\[v' = (2-4x)^{1/3}, v = (3/4) (-1/4) (2-4x)^{4/3}\]

Answer 6

like that

Answer 7

ohhh okay thanks!!