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What are the x-coordinates of the solutions to this system of equations? x2 + y2 = 25 y = 2x − 5 −4 and 0 4 and 0 −3 and −5 3 and −5
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it is a circle and a line, so it will intersect never, once as a tangent, or twice as a secant through th ecircle
They give you the value for y, y=2x-5 put that into the circle equation, and solve for x \[x^2+(2x-5)^2=25\]
i don't know how to do that can you please help
\[x^2+(2x-5)(2x-5)=25\] \[x^2+4x^2-10x -10x+25=25\]
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\[5x^2-20x = 0\] \[5x(x-4) = 0\] \[5x=0~~~~~or~~~~~x-4=0\]
I'm following
if you are following till now , you can finish er
so would it be -4 and 0?
@DanJS
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