Question

Linear algebra question dealing with transpose

Answer 1

I can't figure out how to input matrices here but \[b = \left[\begin{matrix}1 \\ 1 \\ -1 \end{matrix}\right]\]

Answer 2

i figured it out..... find \[b^{T}b\]

Answer 3

what I got was a three by three \[\left[\begin{matrix}1 & 1 & -1\\ 1 & 1 & -1\\ -1 & -1 & 1\end{matrix}\right]\]

Answer 4

just wanted to check and see if this is correct

Answer 5

it should say b*b^T if u got that

Answer 6

3 by 1 matrix * 1by 3 matrix = 3 by 3 matrix,
^--------^---- these inner dimensions have to be equal, that is a way to check if solution exists

Answer 7

rows by columns

Answer 8

Sorry that is correct it should have said b*b^T

Answer 9

would that be correct for b*b^T ?

Answer 10

yes its right

Answer 11

thank you

Answer 12

okay but btw

Answer 13

if u do b^t * b you will get 3

Answer 14

Yeah I actually did that problem first, for some reason I was second guessing myself on this part though

Answer 15

ah okay