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i need help on lesson 8. "what is the perimeter of triangle PQR with the vertices P(-2,9) Q(7,-3) R(-2,-3) in the coordinate plane?"
you need to find the distances between the points of the triangle the distance formula for 2 points in the coordinate plane is d = sqrt([( y2-y1)^2 + (x2 - x1)^2 ] where the 2 points are (x1,y1) and (x2,y2)
so the distance between the points P and Q is sqrt [ (9 - (-3))^2 + ( -2 - 7)^2] = sqrt ( 144 + 81) = sqrt 225 = 15
now you need to find the lengths of the other 2 sides QR and RP by the same method and then the perimeter = sum of these 3 lengths
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