how do I solve v=lwh sove for h
cancel out the `lw` from right side how would you do that ? would add lw both sides subtract or divide ?
can you show me how to cancel
ye it's l times w times h (multiplication ) to cancel out the lw from right you should apply opposite of `multiplication`
so divide both sides by lw
here is an example ab = y (solve for b) so i would divide both sides by a \[\huge\rm \frac{ \cancel{a}b }{ \cancel{a} }=\frac{ y }{ a }\]\ b=y/a
Thank you. how do you solve 5/9(f-32) solve for f
c=5/9
\[\huge\rm c=\frac{ 5 }{ 9 }(f-32)\] like this ?
how do you solve for f
first of all move 5/9 to the left side so multiply both sides by 9/5 let me know what you get after this
45/45
which is equal to what ? 45/45= ?
1
yes right and you have to mutliply 9/5 `both` sides \[\huge\rm \color{blue}{\frac{ 9 }{ 5}} \times c= \frac{ 5 }{ 9 }(f-32) \times \color{blue}{\frac{ 9 }{ 5 }}\]\[\large\rm \color{blue}{\frac{ 9 }{ 5}} \times c= \frac{ \cancel{5} }{\cancel{ 9} }(f-32) \times \color{blue}{\frac{\cancel{ 9} }{ \cancel{5} }}\]\[\large\rm \color{blue}{\frac{ 9 }{ 5 } }\times c =f-32\] now move -32 to the left side
do I still have to add the rest of the equation. once I move -32 to the left
you have to add 32`both` sides
im confused
hmm why ?
because you said to add 32 on both sides. will that include the rest of the equation
solve for `f` right so you need to transfer all the numbers and variables to the left side 32 is negative at right side that's why we should add
yes right
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