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Algebra 18 Online
OpenStudy (anonymous):

how do I solve v=lwh sove for h

Nnesha (nnesha):

cancel out the `lw` from right side how would you do that ? would add lw both sides subtract or divide ?

OpenStudy (anonymous):

can you show me how to cancel

Nnesha (nnesha):

ye it's l times w times h (multiplication ) to cancel out the lw from right you should apply opposite of `multiplication`

Nnesha (nnesha):

so divide both sides by lw

Nnesha (nnesha):

here is an example ab = y (solve for b) so i would divide both sides by a \[\huge\rm \frac{ \cancel{a}b }{ \cancel{a} }=\frac{ y }{ a }\]\ b=y/a

OpenStudy (anonymous):

Thank you. how do you solve 5/9(f-32) solve for f

OpenStudy (anonymous):

c=5/9

Nnesha (nnesha):

\[\huge\rm c=\frac{ 5 }{ 9 }(f-32)\] like this ?

OpenStudy (anonymous):

how do you solve for f

Nnesha (nnesha):

first of all move 5/9 to the left side so multiply both sides by 9/5 let me know what you get after this

OpenStudy (anonymous):

45/45

Nnesha (nnesha):

which is equal to what ? 45/45= ?

OpenStudy (anonymous):

1

Nnesha (nnesha):

yes right and you have to mutliply 9/5 `both` sides \[\huge\rm \color{blue}{\frac{ 9 }{ 5}} \times c= \frac{ 5 }{ 9 }(f-32) \times \color{blue}{\frac{ 9 }{ 5 }}\]\[\large\rm \color{blue}{\frac{ 9 }{ 5}} \times c= \frac{ \cancel{5} }{\cancel{ 9} }(f-32) \times \color{blue}{\frac{\cancel{ 9} }{ \cancel{5} }}\]\[\large\rm \color{blue}{\frac{ 9 }{ 5 } }\times c =f-32\] now move -32 to the left side

OpenStudy (anonymous):

do I still have to add the rest of the equation. once I move -32 to the left

Nnesha (nnesha):

you have to add 32`both` sides

OpenStudy (anonymous):

im confused

Nnesha (nnesha):

hmm why ?

OpenStudy (anonymous):

because you said to add 32 on both sides. will that include the rest of the equation

Nnesha (nnesha):

solve for `f` right so you need to transfer all the numbers and variables to the left side 32 is negative at right side that's why we should add

Nnesha (nnesha):

yes right

Nnesha (nnesha):

|dw:1441637511242:dw|

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