a 500-kg load is supported by a pair of hingeless legs as shown below. There is no friction between the legs and the floor. Find the tension in the rope.

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tinash · Answer

attachment

tinash · Answer

@SolomonZelman  help?

anonymous · Answer

This question entails finding the resulting weight dispersed onto two different legs at equal angles using trigonometry. At first may seem slightly out of hand but as you get at it everything gets easier.

anonymous · Answer

I believe 500kg is a calculated weight.

tinash · Answer

how did you get that? like which formula?

anonymous · Answer

Excuse me mass is usually expressed in kg so consider 500kg as the mass upon which you have to impose 9.8m/s^2 to get the corresponding newton's force.

anonymous · Answer

500kg*9.8m/s^2=corresponding newtons force

tinash · Answer

thank you so much

anonymous · Answer

Now the resulting Newton's force is perpendicular to the ground with frictionless surface so take the newton's force to the perpendicular as the "bisector" of the triangle which makes 2 triangles with a same angle of 65 degrees on each side.

anonymous · Answer

Now use the appropriate trigonometry to calculate the corresponding force on the hypotenuse, and then find the base from the bisector to calculate the force pulling towards opposite direction. Now multiply that force on the bottom of the one half of the triangle by   a factor of 2 to get the tension force acting on the string keeping the structure from collapsing.

anonymous · Answer

End of problem.