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write an equation of the line, in point-slope form. that passes through the given points. (-2,15) and (9,-18)
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\[\LARGE \frac{y_2-y_1}{x_2-x_1}=slope\]
My work \[\left(\begin{matrix}15+18 \\ -2+9\end{matrix}\right)=-\left(\begin{matrix}33 \\ 11\end{matrix}\right)=-\left(\begin{matrix}1 \\ 3\end{matrix}\right)\]
You can divide -33/11 to get a simpler answer :)
-3
Yep :)
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the equation would look like y-2=-3(x-15), right?
y-y1=m(x-x1) y-15=-3(x--2) y-15=-3(x+2)
I think you get confused between y1 and x1 (x,y) <--always that order
I'll take note of that, thank you again
:)
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