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Mathematics 8 Online
OpenStudy (mathmath333):

Sam has forgotten his friend’s seven-digit telephone number. He remembers the following: the first three digits are either 635 or 674, the number is odd, and the number 9 appears once. If Sam were to use a trial and error process to reach his friend, what is the minimum number of trials he has to make before he can be certain to succeed?

OpenStudy (mathmath333):

\(\large \color{black}{\begin{align} & \normalsize \text{ Sam has forgotten his friend’s seven-digit telephone number.}\hspace{.33em}\\~\\ & \normalsize \text{ He remembers the following: the first three digits are either}\hspace{.33em}\\~\\ & \normalsize \text{ 635 or 674, the number is odd, and the number 9 appears }\hspace{.33em}\\~\\ & \normalsize \text{ once. If Sam were to use a trial and error process to reach }\hspace{.33em}\\~\\ & \normalsize \text{ his friend, what is the minimum number of trials he has to }\hspace{.33em}\\~\\ & \normalsize \text{ make before he can be certain to succeed?}\hspace{.33em}\\~\\ & a.)\ 1000 \hspace{.33em}\\~\\ & b.)\ 2430 \hspace{.33em}\\~\\ & c.)\ 3402 \hspace{.33em}\\~\\ & d.)\ 3006 \hspace{.33em}\\~\\ \end{align}}\)

OpenStudy (mathmath333):

r ut yping

imqwerty (imqwerty):

he had to make combinations like - 1)number starting with635 |dw:1441713928711:dw| 1st we take the case where the number has 9 at the end and calculate possibilities nd then u take cases with 1,3,5,7 and fix 9 at one of these points-|dw:1441714010300:dw| and calculate the possibilities nd then multiply it by 3 cause there are 3 such places :) so this way u get possibilities in this case :P similarly do it with 674 :)

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