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Multiply (4x + 7)^2. 16x^2 + 49 16x^2 + 28x + 49 16x^2 + 56x + 49 8x^2 + 14
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(4x + 7) ^2 = (4x + 7)(4x + 7) do you know the FOIL method ?
To solve this I would do (4x + 7)(4x + 7) Correct?
yes
I know how to do it, kind of.. Walk em through it?
me*
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It would be 4x times 4x then 4x times 7?
(4x + 7)(4x + 7) using FOIL -- first,outside,inside,last) First -- multiply first terms in each set....4x * 4x = 16x^2 Outside -- multiply outside terms in each set...4x * 7 = 28x Inside -- multiply inside terms in each set...7 * 4x = 28x Last -- multiply last terms in each set...7 * 7 = 49 put it all together....16x^2 + 28x + 28x + 49 -- combine like terms 16x^2 + 56x + 49 questions ?
Nope, I got it, thank you!
anytime :)
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