Question

Evaluate

Answer 1

g(n-3) means x =n -3 so substitute all x's for n-3

Answer 2

nope b isn't correct
plz show ur steps.

Answer 3

\[\huge\rm \frac{ x^2-2 }{ 5x }\] \[\huge\rm \frac{ (\color{reD}{n-3})^2+2 }{ 5(\color{ReD}{n-3}) }\]

Answer 4

I think that B is wrong

Answer 5

remember:
\[\huge\rm \color{ReD}{a}(b+c)= \color{reD}{a} \times b + \color{reD}{a} \times c = \color{Red}{a}b+\color{ReD}{a}c\]

Answer 6

hint:
when we replace x with n-3, the denominator becomes:
5(n-3)=5*n-5*3=...?