Write the expression -3x squared + 2y squared + 5xy - 2y + 5x squared - 3y squared in simplest form. Then, answer the following questions using complete sentences.

Question

anonymous · Answer

a. How many terms are in the simplified expression?
b. How many of the terms in the simplified expression are negative?

unimatix · Answer

$$-3x^{2}+2y ^{2}+5xy-2y+5x^{2}-3y ^{2}$$
Is this what you have?

anonymous · Answer

yes

anonymous · Answer

i got 32

anonymous · Answer

what is the answer to	x = 2, y = -1

anonymous · Answer

and also x = 0, y = 2.5

texaschic101 · Answer

-3x^2 + 2y^2 + 5xy - 2y + 5x^2 - 3y^2
combine like terms
-3x^2 + 5x^2 = 2x^2
2y^2 - 3y^2 = -y^2
5xy -- no like terms with this
-2y -- no like terms

put it all together..
2x^2 - y^2 + 5xy - 2y -- simplified form

you have 4 terms in the simplified form...
2x^2 is a term, -y^2 is also a term....5xy is a term...and -2y is a term

you have 2 negative terms.....-y^2 and -2y

anonymous · Answer

let me simplify it match up column  A with column B:


	x = 2, y = -1	                                            14	
2.	x = 0, y = 2.5	                                            1.665	
3.	x = -1, y = -3	                                            -11.25	
4.	x = 0.5,y=negative 1/10                           0.44	
5.	x = 3/4, y =2/5 	                                    -1               
6.	x = √2, y = √2	                                            9.17

texaschic101 · Answer

I don't understand what you are supposed to do with these...your just given x and y points....where is the rest of this problem ?

anonymous · Answer

that is what i was given and you match them up

anonymous · Answer

the best you can

texaschic101 · Answer

are you supposed to sub in your x and y points into that first question ?

anonymous · Answer

no they are two different questions

texaschic101 · Answer

then the matching thing makes no sense ....I am sorry but I don't understand.

anonymous · Answer

for number 4 the negative 1/10 is a negative fraction

anonymous · Answer

neither do i that is why i put this question on here

texaschic101 · Answer

Oh crap...I lost track of time....I have to be somewhere in 20 minutes and I am not even ready. You are going to have to tag someone...maybe they will have better luck. Again, I am sorry

anonymous · Answer

please help me out on my second question

unimatix · Answer

Is the second question a sub question of the first one?

texaschic101 · Answer

thats is what I thought...but he said it was a separate question....not related

anonymous · Answer

yea it was i solved the question sorry lol

texaschic101 · Answer

good to hear you solved it :) way to go