Question

Need help please
27x^6-8
factoring the sum or difference of cubes

Answer 1

\[27x ^{6}-8\]

Answer 2

keep in mind I'm factoring the sum or deference of cubues

Answer 3

what is your question

Answer 4

27x^6-8
factoring the sum or difference of cubes

Answer 5

(3x^2)^3-2^3

Answer 6

how did we get there?

Answer 7

\[27x^6-8=3^3(x^2)^3-2^3=(3x^2)^3-2^3\]

Now we use the difference of cubes formula that states \(a^3-b^3=(a-b)(a^2+ab+b^2)\)

Answer 8

Can you please delete the huge space post?

Answer 9

howhow?

Answer 10

got it thanks

Answer 11

and thanks for the help