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find y ' if ((x^2)(y)) + (sec(y)) = 8
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Implicit? :) Ooo these are fun!
is this right ? y'(2x + secy tany) = 0
Hmmm no
im assuming not but i dont know where i went wrong
Did you forget to `product rule` on the first term?
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:D yes i did thank you
Ah you silly billy :d
:P okay how about now 2xy + x^2y'+ y' secy tany = 0
Mmm k looks better! :) Now solve for y', ya?
okay sorry my computer keeps overheating , anyway im getting (-2xy)/(x^2 + secy tany)
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yay good job \c:/
overheating? 0_o oh my
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