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If f(x) = 1/9x - 2 , what is f–1(x)?
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is it \[\huge\rm \frac{ 1 }{ 9x-2 } ~~~or~~\frac{ 1 }{ 9x}-2\]
??
1/9x + 2 is one of the answer
no i'm asking which one is your question first one or 2nd ?is it \[\huge\rm \frac{ 1 }{ 9x-2 } ~~~or~~\frac{ 1 }{ 9x}-2\]
Oh, the second one.
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alright so to find inverse switch `y` and `x` variable f(x) is same as y so \[\huge\rm \color{reD}{y}=\frac{ 1 }{ 9\color{blue}{x} }-2\] inverse would be \[\huge\rm\color{blue}{x}=\frac{ 1}{ 9\color{ReD}{y}}-2\] now solve for y
do you know how to solve that equation for y?
y = 1/9(x+ 2) ?|dw:1441813061513:dw|
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