Question

The temperature at noon was –6.5⁰C. The temperature rose 3.5⁰C from noon to 1 p.m. The temperature decreased t degrees centigrade from 1 p.m. to 2 p.m. The temperature at 2 p.m. was –12⁰C.

Which equation can be used to solve for t?

A.
–6.5 – 3.5 – t = –12

B.
–6.5 + 3.5 + t = –12

C.
–6.5 + 3.5 – t = –12

D.
–6.5 – 3.5 + t = –12

Answer 1

@jacobrocket173

Answer 2

to create the equation add every temp. by its sign, + sign for rose degrees, and - sign for decreased degrees

Answer 3

what ko_O

Answer 4

i got to go sry @fallengoddess

Answer 5

its okay ^_6 see you later

Answer 6

ok your funny

Answer 7

thanks

Answer 8

im back cutie pie

Answer 9

>/////< wb

Answer 10

whats that

Answer 11

welcome back

Answer 12

oh ok can we talk

Answer 13

pm me ok

Answer 14

sry about not being on cause i was at lunch and -6.5 degrees C and rose by 3.5 degrees C, then it decreased by t degrees C and at the end of the it was 12, so reword it
(not giving away the answer, im just rewording it in problem form) -6.5+3.5-t=-12

Answer 15

was - 12*

Answer 16

and i dont see why @jacobciezki got a medal for just talking to you and not even talking about how to do the problem

Answer 17

and for that im reporting him(high chance of doing that

Answer 18

)

Answer 19

hey dont report me

Answer 20

then why did you get a medal for talking to her like your her bae and not like you were helping which you never did help her?

Answer 21

idk ask her

Answer 22

i was going to help but i had to do something

Answer 23

i cant message @fallengoddess to tell her, you gonna have to tell her for me

Answer 24

or ask her i should say