Question

In his famous race, a hare runs for a while, takes a nap, and then resumes running until he reaches the finish line. His total displacement from start to finish is 5.0 m east and 12 m north. The hare's total race time, including the time of napping, is 28 minutes. What is the hare's average speed in meters per minute? someone please help :c

Answer 1

use Pythagoraes to combine the distances...

use the net displacement to get average speed

Answer 2

so 5^2 + 12^2?

Answer 3

yes
\[\sqrt{5^2 + 12^2}\]