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Function problem
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\(\bf f(x)=49-x^2\qquad g(x)=7-x\qquad (f-g)(x)\implies f(x)-g(x) \\ \quad \\ f(x)-g(x)\implies (49-x^2)-(7-x)\)
yes, don't forget to distribute the "-" negative, in front of the parentheses
hmmm did you distribute the negative?
ok... so... let us distribute it -(7-x) = ?
or I should say -(7-x) => -1 * (7-x) => ?
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yeap thus \(\bf f(x)=49-x^2\qquad g(x)=7-x\qquad (f-g)(x)\implies f(x)-g(x) \\ \quad \\ f(x)-g(x)\implies (49-x^2)-(7-x)\implies (49-x^2)-7+x \\ \quad \\ 49-x^2-7+x\implies -x^2+x+42\)
Oh, I see. Thanks so much!
yw
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