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(4^2)^3 • 4^0 do i add the exponents multiply subtract or divide?
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\[((4)^2)^3\]
\[= (4)^{2*3}\]
4^6
good job
ohh so thats the answer right
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almost, now the second part
no i think thats the answer because that is one of my choices
any real number N to the zero power is equal to: \[N ^{0}= 1\]
so Finally, we have :\[4^{6} * 4^{0} =\]
which is 4^6
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yeah because \[4^0 = 1\]
that's all
:)
thnks
YW
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