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Mathematics 8 Online
pooja195 (pooja195):

Lost.

OpenStudy (nightcrawlers_):

And found.

pooja195 (pooja195):

|dw:1441852109149:dw|

OpenStudy (nightcrawlers_):

ewmath im out

pooja195 (pooja195):

@Nnesha @satellite73

OpenStudy (chosenmatt):

lol @NightCrawlers_

OpenStudy (anonymous):

lol

pooja195 (pooja195):

bruh

OpenStudy (anonymous):

what are you looking for ?

Nnesha (nnesha):

trig ? o.O

pooja195 (pooja195):

Side length .-.

OpenStudy (anonymous):

oh i see \[\tan(49)=\frac{14}{x}\]

pooja195 (pooja195):

@Nnesha i dunno what this is my teacher said try it out ima minion -.-

Nnesha (nnesha):

\[\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }\]

OpenStudy (anonymous):

so \[x=\frac{14}{\tan(49)}\] and a calculator

pooja195 (pooja195):

O_o

OpenStudy (chosenmatt):

i'm horrible at math...lol

pooja195 (pooja195):

wht the heck is tan??

Nnesha (nnesha):

familiar with sin ,cos ,tan ratioS ?

pooja195 (pooja195):

nope .-.

OpenStudy (nightcrawlers_):

@chosenmatt preech it. no one needs math anyways

OpenStudy (anonymous):

you can't do with without trig

OpenStudy (chosenmatt):

lol

pooja195 (pooja195):

with? without trig?

OpenStudy (anonymous):

i am looking at the one in the blue box is that the one you need help with?

pooja195 (pooja195):

Ye

OpenStudy (nightcrawlers_):

i have an idea. stop. drop. and then cheese.

OpenStudy (chosenmatt):

oh i got this!!! (not really)

pooja195 (pooja195):

:3 <----Cheese.

OpenStudy (chosenmatt):

i'll be suprise af if i get this right tho lol

pooja195 (pooja195):

Now help ._. ;~; i need to get this done!

OpenStudy (anonymous):

lot of chatter here

pooja195 (pooja195):

i didnt notice.

OpenStudy (chosenmatt):

ok has a x on it so we don't have to do it...problem solved...xD lol

pooja195 (pooja195):

-_-

OpenStudy (anonymous):

tangent is a function as a functions of angles in a right triangle it is the length of the "opposite side" divided by the length of the "adjacent" side

pooja195 (pooja195):

Got it.

Nnesha (nnesha):

|dw:1441852380270:dw| given is opposite side which is 14 and you have to solve for x which is adjacent of 49 degree aand tangent = opposite over adjacent

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