Question

How many three different digit numbers can be formed using the digits 2,3,5,6,7. ASAP with process

Answer 1

can we repeat?

Answer 2

We have to find how many of 3-digit numbers can be formed by using 2,3,5,6,7. When every digit should be different in the number

Answer 3

In the first digit you can have 5 different numbers (all the digits), then in the second you can have 5-1=4 possible numbers because it cannot be equal to the first digit. Then in the third digit you are left with only 4-1=3 possible digits because two of them have been already used in the first two places. Therefore 5x4x3=60 possible combinations.

Answer 4

Using permutation you can solve this problem as -
First place can be filled with 5 ways
Second place can be filled with 4 ways
Third place can be filled with 3 ways
So ,answer is 5*4*3=60