Question

Find the solution of 4 times the square root of the quantity of x plus 2 equals negative 16, and determine if it is an extraneous solution.

x = 14; not extraneous
x = 2; extraneous
x = 2; not extraneous
x = 14; extraneous

Answer 1

\[4\sqrt{x+2}=-16\]

Answer 2

any ideas on how to start?

Answer 3

You would move -16 to the left side, and set it equal to 0?

Answer 4

I'd divide by the 4.

Answer 5

It's not a polynomial, so you don't have to set it equal to 0

Answer 6

So I'd have? \[\frac{ \sqrt{x+2} }{ 4 }=-4\]