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Solve for x, given the equation Square root of x minus 5+ 7 = 11.
x = 21, solution is extraneous
x = 21, solution is not extraneous
x = 81, solution is extraneous
x = 81, solution is not extraneous
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OpenStudy (agl202):
@ganeshie8 hlp.. plz...
Nnesha (nnesha):
\[\huge\rm \sqrt{x-5}+7=11\] like this ?
Nnesha (nnesha):
or 7 is also under the root ?
OpenStudy (agl202):
So it would be x=21 right?
OpenStudy (agl202):
So, A.?
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Nnesha (nnesha):
what is an extraneous and non-extraneous solution means ?
OpenStudy (agl202):
Extraneous Solution is a solution of the simplified form of an equation that does not satisfy the original equation.
Nnesha (nnesha):
okay.
substitute x for its value into the original equation
if both sides are equal then 21 isn't extraneous solution
if both sides aren't equal then 21 is an extraneous solution
Nnesha (nnesha):
\[\huge\rm \sqrt{x-5}+7=11\] replace x with 21
solve left side
OpenStudy (agl202):
I don't get it. ^
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Nnesha (nnesha):
x=21 right
now to check if it's an extraneous or non-extraneous you should substitute x for 21
OpenStudy (agl202):
I get a non-extraneous.
Nnesha (nnesha):
right \[\sqrt{21-5}+7=11\] both sides are equal so it would be non-ex
OpenStudy (agl202):
You deserve a medal! Thx u so much!!! :D
Nnesha (nnesha):
yw!
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