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Algebra 23 Online
OpenStudy (clamin):

PLEASE HELP!! MEDAL!!

OpenStudy (clamin):

\[108a ^{3}+32\]

OpenStudy (clamin):

factor completely

OpenStudy (anonymous):

so a common factor between 108 and 32 is 4

OpenStudy (anonymous):

4 ( 27x^3 + 8) so now we can factor 27^3 + 8

OpenStudy (anonymous):

that's a perfect cube, so: 27x^3 + 8 = (3x + 2) (x^2 - 6x + 4) and the fully factored version would be: 4 (3x+2)(x^2-6x+4) did that make sense?

OpenStudy (clamin):

yes..thank you

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